(ln(1-x^2))^3/2

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Solution for (ln(1-x^2))^3/2 equation: 


D( x )

1-x^2 <= 0

1-x^2 <= 0

1-x^2 <= 0

-1*x^2 <= -1

-1*x^2 <= -1 // * -1

1*x^2 >= 1

1*x^2 >= 1 // : 1

x^2 >= 1/1

x^2 >= 1

x^2 >= 1 // ^ 1/2

abs(x) >= 1

x in (-oo:-1> U <1:+oo)

x in (-1:1)

((ln(1-x^2))^3)/2 = 0

t_1 = ln(1-x^2)

(t_1^3)/2 = 0

1/2*t_1^3 = 0 // : 1/2

t_1^3 = 0

t_1 = 0

ln(1-x^2) = 0

ln(1-x^2) = ln(e^0)

1-x^2 = e^0

1-x^2-e^0 = 0

-1*x^2 = 0 // : -1

x^2 = 0

x = 0

x = 0

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